Python删除小数点后多余的0

问题描述

删除小数点后多余的0

输入

12.22
12.20
12.0

输出

12.22
12.2
12

解决方案

判断类型并结合字符串的rstrip()

def delete_extra_zero(n):
    '''删除小数点后多余的0'''
    if isinstance(n, int):
        return n
    if isinstance(n, float):
        n = str(n).rstrip('0')  # 删除小数点后多余的0
        n = int(n.rstrip('.')) if n.endswith('.') else float(n)  # 只剩小数点直接转int，否则转回float
        return n


if __name__ == '__main__':
    print(delete_extra_zero(12.22))  # 12.22
    print(delete_extra_zero(12.20))  # 12.2
    print(delete_extra_zero(12.0))  # 12
    print(delete_extra_zero(12))  # 12
    print(delete_extra_zero(120))  # 120

解决方案2

感谢 YnagShanwen 提供的方案

def delete_extra_zero(n):
    """删除小数点后多余的0"""
    n = '{:g}'.format(n)
    n = float(n) if '.' in n else int(n)  # 含小数点转float否则int
    return n


if __name__ == '__main__':
    print(delete_extra_zero(12.22))  # 12.22
    print(delete_extra_zero(12.20))  # 12.2
    print(delete_extra_zero(12.02))  # 12.02
    print(delete_extra_zero(12.0))  # 12
    print(delete_extra_zero(12))  # 12
    print(delete_extra_zero(120))  # 120

参考文献

1. python中输出时如何省略小数末位的零？
2. 格式字符串语法 — Python文档